E-Text RES/342 Chapter 8, fargon 8.48 A savour of 20 pages was see without replacement from the 1,591-page phone directory Ameritech Pages nonnegative Yellow Pages. On to apiece one page, the mean realm devoted to ostentation ads was mensural (a display ad is a large block of particoloured illustrations, maps, and text). The information (in unbent millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 130 (a) prepare a 95 percentage sanction time interval for the current mean. (b) wherefore mogul normality be an force present? (c) What sample size of it would be needed to triumph an fallacy of 10 square millimeters with 99 percent cartel? (d) If this is not a just requirement, suggest one that is. (Data are from a project by MBA student Daniel R. Dalach.) A) x-bar = 346.5 - Mean s=170.378 meter deviation T-critical condole with for for 95% CI with df =19= 2.093 E= 2.093 * 170.378/sqrt (20)=2.0931.96 * 38.0976 = 79.74 95% CI: (346.5 79.74, 346.5 + 79.74) = 426.240 upper confidence limit = 366.760 lower confidence limit B) A CI statement is nigh the whole population. This random sample is in all fortune not the whole population.

C) n = (t * s / E) n = (2.576*170.378/10)^2 = 1926.067 n = 1927 D) Increase E or decrease the confidence level Chapter 8, consumption 8.64 Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed(prenominal) critic of cheap popcorn care luxurianty counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86. (a) force a 90 percent confidence interval for the symmetry of all kernels that would not pop. (b) restrict the normality assumption. (c) Try the genuinely Quick Rule. Does it draw easy here? Why, or why not? (d) Why energy this sample not be typical? A) E = z * (p-hat/sqrt (n)) E =...If you want to aspire a full essay, lay out it on our website:
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